 Degree of Reaction
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Degree of Reaction

In turbomachinery, Degree of reaction or reaction ratio (R) is defined as the ratio of the static pressure drop in the rotor to the static pressure drop in the stage or as the ratio of static enthalpy drop in the rotor to the static enthalpy drop in the stage.

Degree of reaction (R) is an important factor in designing the blades of a turbine, compressors, pumps and other turbo-machinery. It also tells about the efficiency of machine and is used for proper selection of a machine for a required purpose.

Various definitions exist in terms of enthalpies, pressures or flow geometry of the device. In case of turbines, both impulse and reaction machines, Degree of reaction (R) is defined as the ratio of energy transfer by the change in static head to the total energy transfer in the rotor i.e.

$R={\frac {\text{Isentropic enthalpy change in rotor}}{\text{Isentropic enthalpy change in stage}}}$ .

For a gas turbine or compressor it is defined as the ratio of isentropic heat drop in the moving blades (i.e. the rotor) to the sum of the isentropic heat drops in the fixed blades (i.e. the stator) and the moving blades i.e.

$R={\frac {\text{Isentropic heat drop in rotor}}{\text{Isentropic heat drop in stage}}}$ .

In pumps, degree of reaction deals in static and dynamic head. Degree of reaction is defined as the fraction of energy transfer by change in static head to the total energy transfer in the rotor i.e.

$R={\frac {\text{Static pressure rise in rotor}}{\text{Total pressure rise in stage}}}$ .

## Relation

Most turbo machines are efficient to a certain degree and can be approximated to undergo isentropic process in the stage. Hence from $Tds=dh-{\frac {dp}{\rho }}$ ,

it is easy to see that for isentropic process ?H ? ?P. Hence it can be implied

$R={\frac {\Delta H{\text{ (Rotor)}}}{\Delta H{\text{ (Stage)}}}}$ The same can be expressed mathematically as:

$\ R={\frac {\int _{3ss}^{2s}{\textrm {dh}}}{\int _{3ss}^{1}{\textrm {dh}}}}\,\ {\textrm {Or}}\,\ {\frac {\int _{3ss}^{2s}{\textrm {dp}}}{\int _{3ss}^{1}{\textrm {dp}}}}$ Where 1 to 3ss in Figure 1 represents the isentropic process beginning from stator inlet at 1 to rotor outlet at 3. And 2 to 3s is the isentropic process from rotor inlet at 2 to rotor outlet at 3. The velocity triangle (Figure 2.) for the flow process within the stage represents the change in fluid velocity as it flows first in the stator or the fixed blades and then through the rotor or the moving blades. Due to the change in velocities there is a corresponding pressure change.

Another useful definition used commonly uses stage velocities as:

$\,h_{2}-h_{3}={1 \over {2}}(V_{r3}^{2}-V_{r2}^{2})+{1 \over {2}}(U_{2}^{2}-U_{3}^{2})$ is the enthalpy drop in the rotor and

$\,h_{01}-h_{03}=h_{02}-h_{03}=(U_{2}\,V_{w2}-U_{1}\,V_{w1})$ is the total enthalpy drop. The degree of reaction is then expressed as

$R={\frac {[{1 \over {2}}(V_{r3}^{2}-V_{r2}^{2})+{1 \over {2}}(U_{2}^{2}-U_{3}^{2})]}{(U_{2}\,V_{w2}-U_{1}\,V_{w1})}}$ For axial machines $U2=U1=U$ , then

$R={\frac {(V_{r3}^{2}-V_{r2}^{2})}{2U(V_{w3}+V_{w2})}}$ The degree of reaction can also be written in terms of the geometry of the turbomachine as obtained by

$R=({\frac {V_{f}}{2U}})(\tan {\beta _{3}}-\tan {\beta _{2}})$ where $\beta _{3}$ is the vane angle of rotor outlet and $\beta _{2}$ is the vane angle of stator outlet. In practice $({\frac {V_{f}}{2U}})$ is substituted as ? and $(\tan {\beta _{3}}-\tan {\beta _{2}})$ as $\tan {\beta _{m}}$ giving$R=\phi \tan {\beta _{m}}.$ The degree of reaction now depends only on ? and $\tan {\beta _{m}}$ which again depend on geometrical parameters ?3 and ?2 i.e. the vane angles of stator outlet and rotor outlet. Using the velocity triangles degree of reaction can be derived as:

$R={\frac {1}{2}}+{\frac {V_{f}}{2U}}(\tan {\beta _{3}}-\tan {\alpha _{2}})$ This relation is again very useful when the rotor blade angle and rotor vane angle are defined for the given geometry.

## Choice of reaction (R) and effect on efficiency

The Figure 3 alongside shows the variation of total-to-static efficiency at different blade loading coefficient with the degree of reaction. The governing equation is written as

$R=1+{\frac {\Delta W}{2U^{2}}}-{\frac {C_{y2}}{U}}$ where ${\frac {\Delta W}{2U^{2}}}$ is the stage loading factor. The diagram shows the optimization of total - to - static efficiency at a given stage loading factor, by a suitable choice of reaction. It is evident from the diagram that for a fixed stage loading factor that there is a relatively small change in total-to-static efficiency for a wide range of designs.

### 50% reaction

The degree of reaction contributes to the stage efficiency and thus used as a design parameter. Stages having 50% degree of reaction are used where the pressure drop is equally shared by the stator and the rotor for a turbine.

This reduces the tendency of boundary layer separation from the blade surface avoiding large stagnation pressure losses.

If R= ​ then from the relation of degree of reaction,|C| ?2 = ?3 and the velocity triangle (Figure 4.) is symmetric. The stage enthalpy gets equally distributed in the stage (Figure 5.) . In addition the whirl components are also the same at the inlet of rotor and diffuser.

### Reaction less than 50%

Stage having reaction less than half suggest that pressure drop or enthalpy drop in the rotor is less than the pressure drop in the stator for the turbine. The same follows for a pump or compressor as shown in Figure 6. Therefore the stator has a larger contribution to the total work extracted or work done. From the relation for degree of reaction, |C| ?2 > ?3.

### Reaction more than 50%

Stage having reaction more than half suggest that pressure drop or enthalpy drop in the rotor is more than the pressure drop in the stator for the turbine. The same follows for a pump or compressor. Thus in this case the rotor has a larger contribution to the total work extracted or work done. From the relation for degree of reaction,|C| ?2 < ?3 which is also shown in corresponding Figure 7.

### Reaction = zero

This is special case used for impulse turbine which suggest that entire pressure drop in the turbine is obtained in the stator. The stator performs a nozzle action converting pressure head to velocity head and extracting work. It is difficult to achieve adiabatic expansion in the impulse stage, i.e. expansion only in the nozzle, due to irreversibility involved, in actual practice. Figure 8 shows the corresponding enthalpy drop for the reaction = 0 case.