1812 United States Presidential Election in Ohio
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1812 United States Presidential Election in Ohio
1812 United States presidential election in Ohio

← 1808 1812 1816 →
  James Madison.jpg DeWitt Clinton by Rembrandt Peale.jpg
Nominee James Madison DeWitt Clinton
Party Democratic-Republican Federalist
Home state Virginia New York
Running mate Elbridge Gerry Jared Ingersoll
Electoral vote 8 0
Popular vote 7,420 3,301
Percentage 69.21% 30.79%

The 1812 United States presidential election in Ohio took place as part of the 1812 United States presidential election. Voters chose 8 representatives, or electors to the Electoral College, who voted for President and Vice President.

Ohio re-elected incumbent Democratic-Republican President James Madison over Federalist candidate DeWitt Clinton. Madison won Ohio by a margin of 38.42%.

Results

1816 United States presidential election in Ohio[1]
Party Candidate Votes Percentage Electoral votes
Democratic-Republican James Madison 7,420 69.21% 8
Federalist DeWitt Clinton 3,301 30.79% 0
Totals 10,721 100.0% 8

References

  1. ^ Ohio. Secretary of State. (1909). Ohio election statistics: the general election. Springfield, Ohio: The Springfield Publishing Company, State Printers. p. 3. OCLC 5470967. Retrieved .



  This article uses material from the Wikipedia page available here. It is released under the Creative Commons Attribution-Share-Alike License 3.0.

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